I have a large book with like 1000 brain teasers and puzzles. I will post some of them here later.

# Challenge Math and Brain Teaser Problems!

**MR.GAM3R**#183

Here is the first riddle. This one is quite easy, in my opinion. (Rated difficulty 6 in the book)

Three models, Miss Pink, Miss Green and Miss Blue are on the catwalk. Their dresses are pink, green, and blue.

"It's strange," Miss Blue remarks to the others. "We are named Pink, Green and Blue, and our dresses are pink, green, and blue, but none of us is wearing the dress that matches her name."

"That *is* a coincidence," says the woman in green.

From that information, can you determine the colour of each model's dress?

Remember to put your answers in [spoiler][/spoiler] tags!

**NindroidGames**#184

Hmmmm... is it Pink is wearing green, blue pink, and green blue? That's assuming the two speakers were different.

**XiaoMiaoMi**#186

do we assume that the models can only see the other models' dresses, or that they can see their own, too?

and are we assuming here that the models all have functioning logical thinking capabilities?

EDIT: OOPS USED THE WRONG APPROACH THIS QUESTION DOESN'T NEED THAT LEVEL OF METAQUESTIONING

**XiaoMiaoMi**#187

okay i *way* overthought that haha

answer: miss blue is wearing pink, miss green blue, and miss pink green.

## my steps for anyone who's just too tired and wants a quick answer to the question w/o stressing

my initial approach was "look at what each model could see the others wearing, and from there figure out what each model is thinking". way, way overthought the problem.

the correct and easier approach, however, was to look at the discussion.

**1): miss blue cannot be wearing green, as the person replying to her is wearing green.**

therefore, we are left with two things miss blue can wear: pink, and blue. and, of course, miss blue *can't wear her own color*, so she must be wearing pink.

**2) the person wearing green can't be miss green or miss blue**

miss green *can't wear her own color*, and miss blue is wearing pink, as said above. therefore, we are left with one choice: miss pink must be wearing green!

**3) process of elimination**

we are left with one more person and one more dress: miss green and the blue dress.

**MR.GAM3R**#192

Here is another one that I am still in the process of solving.

On every birthday since I was born, I have had a birthday cake decorated with the appropriate number of candles. So far I have blown 210 candles. How old am I?

Make sure you put your answers in [spoiler][/spoiler] tags!

**JonnyGamer**#195

This has to do with triangle, numbers! Awesome!

## All about triangle numbers

This is a great question, and has to do a lot with triangle numbers!

First, I'll explain what they are: a triangle number is like a factorial (n!), but instead of multpliyong together all the previous numbers, you add them together.

There's a formula for finding triangular numbers, which is derived form the patter of 1, 1 + 2, 1 + 2 + 3, ...

It follows a right triangle using dots (I'll provide a link for this!)

n * ( n + 1 )

–––––––

2

Now that we are talking about it, this is why square numbers are called square! It makes a square pattern when you increase which gives you the formula:

n*n

Also! A square number can be trianglular! Can you find any examples??

Lastly, there are numbers such as pentagonal, hexagonal, septagonal, ... , myriagonal!

Here's links to these that explain them better:

Hope this helped! This stuff is great!

## Answer to the problem

20 years

JonnyGamer and t1's Math Blog!

JonnyGamer and t1's Math Blog!

**Stradyvarious**#196

A man is trapped in a room. The room has only two possible exits: two doors. Through the first door there is a room constructed from magnifying glass. The blazing hot sun instantly fries anything or anyone that enters. Through the second door there is a fire-breathing dragon. How does the man escape?

**JonnyGamer**#198

## I've heard this before, but I don't remember the answer!

There are no windows, so how can the magnifying glass magnify anything??

**MR.GAM3R**#202

Cool. I hadn't seen that formula before, so I actually worked one out myself although it isn't as simple